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Caramel11111
@Caramel11111
August 2022
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Помогите решить пожалуйста
Упростите выражение(1/a²+2ab-1/a²-2ab):4b²/4b²-a2 и найдите его значение при a=-1;b=1
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sedinalana
Verified answer
1)1/[a(a+2b)]-1/[a(a-2b)]=(a-2b-a-2b)/[a(a-2b)(a+2b)]=-4b/[a(a-2b)(a+2b)]
2)4b/[a(2b-a)(2b+a)]*(2b-a)(2b+a)/4b²=1/ab
a=-1,b=1 1/(-1*1)=-1
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Answers & Comments
Verified answer
1)1/[a(a+2b)]-1/[a(a-2b)]=(a-2b-a-2b)/[a(a-2b)(a+2b)]=-4b/[a(a-2b)(a+2b)]2)4b/[a(2b-a)(2b+a)]*(2b-a)(2b+a)/4b²=1/ab
a=-1,b=1 1/(-1*1)=-1