4б) f(x)=e^sinx; x=0...

July 2022 1 16 Report

найдите производную функциинайдите производную функции
а) f(x)=cos5x
б) f(x)=√9-x²
и найдите производную функции при данном значении аргумента
а) f(x)=cos²x; x= -π/4
б) f(x)=e^sinx; x=0

Answers & Comments

maslena76 А) $f'=-5sin5x$
б) $f'= \frac{-2x}{2 \sqrt{9- x^{2} } } = \frac{-x}{ \sqrt{9- x^{2} } }$
а) $f'=2cosx(-sinx)=-sin2x$
$f'( -\frac{ \pi }{4} )=-sin2*(-\frac{ \pi }{4})=sin\frac{ \pi }{2}=1$
б) $f'=cosx*e ^{ sinx}$
$f'(0)=cos0*e^0=1$

2 votes Thanks 1

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