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madina181100
@madina181100
August 2021
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(4b^2+2a^2-4ab)(3ab+2a^3-3b^2)
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mrrevis95
=12ab^3+8a^3b^2-12b^4+6a^3b+4a^5-6a^2b^2-12a^2b^2-8a^4b+12ab^2=12ab^3+8a^3b^2-12b^4+6a^3b+4a^5-18a^2b^2-8a^4b+12ab^2
5 votes
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