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meryert2004
@meryert2004
July 2022
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8/27a^3-1/64b^3=(2/3a-1/2b)(4/9a^2+1/12ab+1/4b^2)
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Доказать ???
(1) (8/27)a^3-(1/64)b^3=((2/3)a-1/2b)((4/9)a^2+(1/12)ab+(1/4)b^2)
(8/27)·a^3-(1/64)·b^3=((2/3)a)^3-((1/4)b)^3=[(2/3)·a-(1/4)b]·[((2/3)a)^2+(2/3)a·(1/4)b+((1/4)b)^2]=((2/3)a-1/2b)((4/9)a^2+(1/12)ab+(1/16)b^2) (2)
(1/4)b^2) - последнее слагаемое (1) не совпадает с последним слагаемым (2) , скорее не верно записано...
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Verified answer
Доказать ???(1) (8/27)a^3-(1/64)b^3=((2/3)a-1/2b)((4/9)a^2+(1/12)ab+(1/4)b^2)
(8/27)·a^3-(1/64)·b^3=((2/3)a)^3-((1/4)b)^3=[(2/3)·a-(1/4)b]·[((2/3)a)^2+(2/3)a·(1/4)b+((1/4)b)^2]=((2/3)a-1/2b)((4/9)a^2+(1/12)ab+(1/16)b^2) (2)
(1/4)b^2) - последнее слагаемое (1) не совпадает с последним слагаемым (2) , скорее не верно записано...