[tex] \frac{ {4c}^{2} - {25x}^{2} }{ {4c}^{2} + 20cx + {25x}^{2} } = \frac{(2c - 5x)(2c + 5x)}{ {(2c + 5x)}^{2} } = \frac{2c - 5x}{2c + 5x} \\ [/tex]
Ответ:вот
Объяснение:
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[tex] \frac{ {4c}^{2} - {25x}^{2} }{ {4c}^{2} + 20cx + {25x}^{2} } = \frac{(2c - 5x)(2c + 5x)}{ {(2c + 5x)}^{2} } = \frac{2c - 5x}{2c + 5x} \\ [/tex]
Ответ:вот
Объяснение: