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YanaSavenkova
@YanaSavenkova
July 2022
1
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Вычислите:
1)tg^2 30°+2sin60°-tg45°+cos^2 30°
2)ctg^2 45°+cos60°-sin^2 60°+3/4ctg^2 60
°
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avilov41
Решение:
1) tg^230°+2sin60°-tg45°+cos^230°=
=(1/√3)^2+2√3/2-1+(√3/2)^2=1/3+√3-1+3/4=1/12+√3.
2)ctg^245°+cos60°-sin^260+3/4ctg^260°=
=1+1/2-3/4+3/4*1/3=1/3+√3.
4 votes
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Answers & Comments
1) tg^230°+2sin60°-tg45°+cos^230°=
=(1/√3)^2+2√3/2-1+(√3/2)^2=1/3+√3-1+3/4=1/12+√3.
2)ctg^245°+cos60°-sin^260+3/4ctg^260°=
=1+1/2-3/4+3/4*1/3=1/3+√3.