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Alyako
@Alyako
July 2022
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в момент времени t=1 найдите скорость и ускорение точки движушейся прямолинейно по знакому s=sin((пи*t)/4)
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mikael2
V=s'=cos(πt/4)*π/4 v(1)=π/4*cosπ/4=π/4*√2/2
a(1)=v'=-π²/16*sinπ/4=-π²/16*√2/2=-√2*π²/32
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Answers & Comments
a(1)=v'=-π²/16*sinπ/4=-π²/16*√2/2=-√2*π²/32