[tex]3ab^4=5\; \; = > \; \; ab^4=\frac{5}{3}\\\\1)\; 1,2ab^4=1,2*\frac{5}{3}=\frac{6}{3}=2\\\\2)\; -12a^2b^8=-12(ab^4)^2=-12*(\frac{5}{3})^2=-12*\frac{25}{9}=-\frac{4*25}{3}=-\frac{100}{3}=-33\frac{1}{3}[/tex]
Ответ: [tex]1)\; 2;\; 2)\; -33\frac{1}{3}[/tex]
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[tex]3ab^4=5\; \; = > \; \; ab^4=\frac{5}{3}\\\\1)\; 1,2ab^4=1,2*\frac{5}{3}=\frac{6}{3}=2\\\\2)\; -12a^2b^8=-12(ab^4)^2=-12*(\frac{5}{3})^2=-12*\frac{25}{9}=-\frac{4*25}{3}=-\frac{100}{3}=-33\frac{1}{3}[/tex]
Ответ: [tex]1)\; 2;\; 2)\; -33\frac{1}{3}[/tex]