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pokipoki
@pokipoki
July 2022
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Упростить и найти значение выражения
4sin(x/7)*cos(x/7)*cos(2x/7),при Х=7П/4
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Хильмилли
4sin(x/7)*cos(x/7)*cos(2x/7)=2*2*
sin(x/7)*cos(x/7)*cos(2x/7)=
=2*sin(
2x/7)*
cos(2x/7)
=sin(4x/7)
x=7π/4⇒sin(4x/7)=sin(4/7*7π/4)=sinπ=0
2 votes
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Answers & Comments
=2*sin(2x/7)*cos(2x/7)=sin(4x/7)
x=7π/4⇒sin(4x/7)=sin(4/7*7π/4)=sinπ=0