Відповідь:
Пояснення:
1) 2(x-4)-2(5-6x) = 18
2x - 8 - 10 + 12x = 18
14x - 18 = 18
14x = 36
x = 36/14 або x = 18/7
2) 9(y+2)=8(1- y) +24
9y + 18 = 8 - 8y + 24
9y + 18 = 16 - 8y + 24
9y = -10 - 8y + 24
17y = 14
y = 14/17
3) 0,4x-2,6-5(0,2-x)-0,3(x+4)
0,4x - 2,6 - 1 + 5x - 0,3x - 0,3 * 4
5,1x - 5,8
4) 0,5(2-x)+2(4x-0,2)+5,9=-5,5x
1 - 0,5x + 8x - 0,4 + 5,9 = -5,5x
8,5x + 6,5 = -5,5x
14x + 6,5 = 0
14x = -6,5
x = -6,5 / 14
[tex]\displaystyle\bf\\1)\\\\2(x-4)-2(5-6x)=18\\\\x-4-(5-6x)=9\\\\x-4-5+6x=9\\\\7x-9=9\\\\7x=18\\\\\boxed{x=2\frac{4}{7} }\\\\2)\\\\9(y+2)=8(1-y)+24\\\\9y+18=8-8y+24\\\\9y+8y=32-18\\\\17y=14\\\\\boxed{y=\frac{14}{17} }\\\\3)\\\\0,4x-2,6=5(0,2-x)-0,3(x+4)\\\\0,4x-2,6=1-5x-0,3x-1,2\\\\0,4x+5,3x=1-1,2+2,6\\\\5,7x=2,4\\\\x=\frac{24}{57} =\frac{8}{19} \\\\\boxed{x=\frac{8}{19}} \\\\4)[/tex]
[tex]\displaystyle\bf\\0,5(2-x)+2(4x-0,2)+5,9=-5,5x\\\\1-0,5x+8x-0,4+5,9=-5,5x\\\\7,5x+5,5x=-6,5\\\\13x=-6,5\\\\x=-\frac{6,5}{13} =-\frac{65}{130} =-\frac{1}{2}=-0,5\\\\\boxed{x=-0,5}[/tex]
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Відповідь:
Пояснення:
1) 2(x-4)-2(5-6x) = 18
2x - 8 - 10 + 12x = 18
14x - 18 = 18
14x = 36
x = 36/14 або x = 18/7
2) 9(y+2)=8(1- y) +24
9y + 18 = 8 - 8y + 24
9y + 18 = 16 - 8y + 24
9y = -10 - 8y + 24
17y = 14
y = 14/17
3) 0,4x-2,6-5(0,2-x)-0,3(x+4)
0,4x - 2,6 - 1 + 5x - 0,3x - 0,3 * 4
5,1x - 5,8
4) 0,5(2-x)+2(4x-0,2)+5,9=-5,5x
1 - 0,5x + 8x - 0,4 + 5,9 = -5,5x
8,5x + 6,5 = -5,5x
14x + 6,5 = 0
14x = -6,5
x = -6,5 / 14
[tex]\displaystyle\bf\\1)\\\\2(x-4)-2(5-6x)=18\\\\x-4-(5-6x)=9\\\\x-4-5+6x=9\\\\7x-9=9\\\\7x=18\\\\\boxed{x=2\frac{4}{7} }\\\\2)\\\\9(y+2)=8(1-y)+24\\\\9y+18=8-8y+24\\\\9y+8y=32-18\\\\17y=14\\\\\boxed{y=\frac{14}{17} }\\\\3)\\\\0,4x-2,6=5(0,2-x)-0,3(x+4)\\\\0,4x-2,6=1-5x-0,3x-1,2\\\\0,4x+5,3x=1-1,2+2,6\\\\5,7x=2,4\\\\x=\frac{24}{57} =\frac{8}{19} \\\\\boxed{x=\frac{8}{19}} \\\\4)[/tex]
[tex]\displaystyle\bf\\0,5(2-x)+2(4x-0,2)+5,9=-5,5x\\\\1-0,5x+8x-0,4+5,9=-5,5x\\\\7,5x+5,5x=-6,5\\\\13x=-6,5\\\\x=-\frac{6,5}{13} =-\frac{65}{130} =-\frac{1}{2}=-0,5\\\\\boxed{x=-0,5}[/tex]