(4х ^ (2)-9)(25-х ^ (2))(3х ^ (2)+2)>0 Решите пожалуйста. Created by Katyusha5. algebra-ru

(4х ^ (2)-9)(25-х ^ (2))(3х ^ (2)+2)>0 Решите пожалуйста...

Katyusha5 @Katyusha5

August 2022 1 12 Report

(4х ^ (2)-9)(25-х ^ (2))(3х ^ (2)+2)>0 Решите пожалуйста

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Anastsiia

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Метод интервалов:
$(4 x^{2} -9)(25- x^{2} )(3 x^{2} +2)>0 \\ 
(2 x -3)(2x+3)(5-x )(5+x)(3 x^{2} +2)>0 \\ x_1=3/2; \ x_2=-3/2; \ x_3=5; \ x_4=-5; \ 3 x^{2} +2 \neq 0 \\ 
x \in (-5;-3/2) \cup (3/2;5)$

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