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Rinka120
@Rinka120
August 2022
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4(х-4)(х+8)=(3х+2)(х-5)+(х-1)(х+1)
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kdid
4(х-4)(х+8)=(3х+2)(х-5)+(х-1)(х+1)
4(x²+8x-4x-32)=3x²-15x+2x-10+x²+x-x-1
4x²+32x-16x-128=4x²-13x-11
4x²+16x-4x²+13x=128-11
29x=117
x=117/29
x=4 1/29
1 votes
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Answers & Comments
4(x²+8x-4x-32)=3x²-15x+2x-10+x²+x-x-1
4x²+32x-16x-128=4x²-13x-11
4x²+16x-4x²+13x=128-11
29x=117
x=117/29
x=4 1/29