4х^2-y=2 2x^2+y=4 решите систему. Created by zubarevadaria44. algebra-ru

4х^2-y=2 2x^2+y=4 решите систему...

Evgenia4836

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Складываем уравнения, получаем

6x²=6
y=4x²-2

x²=1
y=4x²-2

x1=1
y1=2

x2= -1
y2=2
Ответ: (1;2) и (-1;2)

0 votes Thanks 2

zhenyaM2002

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{ 4х² - у = 2
{ 2х² + у = 4
Способ сложения:
4х² - у + 2х² + у = 2 + 4
6х² = 6
х² = 6 : 6
х² = 1
х² - 1² = 0
(х - 1)(х + 1) = 0
х - 1 = 0
х₁ = 1
х + 1 = 0
х₂ = - 1

2 * 1² + у = 4
2 +у = 4
у = 4 - 2
у₁ = 2

2* (-1)² + у = 4
2 + у = 4
у = 4-2
у₂ = 2

Ответ : ( 1 ; 2) , (- 1 ; 2) .

1 votes Thanks 1

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