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1234555598
@1234555598
August 2022
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-4(х+3)=0
-5у(у-2)(у+9)=0
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niktory
1) -4(х+3)=0
-4х -12 = 0
-4х = 12
х = 12 : (-4)
х = -3
2)
-5у(у-2)(у+9)=0
-5y(у²-2у+9у-18)=0
-5y(у²+7у-18)=0
-5у=0 у²+7у-18=0
у1=0 D=b²-4ac=7²-4*1*(-18)=49+72=121
y2= (-b-√D)/2a = (-7-√121)/2*1 = -18/2=-9
y3=(-7+√121)/2*1 = 4/2=2
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1234555598
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Answers & Comments
-4х -12 = 0
-4х = 12
х = 12 : (-4)
х = -3
2) -5у(у-2)(у+9)=0
-5y(у²-2у+9у-18)=0
-5y(у²+7у-18)=0
-5у=0 у²+7у-18=0
у1=0 D=b²-4ac=7²-4*1*(-18)=49+72=121
y2= (-b-√D)/2a = (-7-√121)/2*1 = -18/2=-9
y3=(-7+√121)/2*1 = 4/2=2