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yulia08082007
@yulia08082007
July 2022
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(4p-q)^2-(2p+3q)^2 (разложите на множители)
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Lesben
(4p-q)²-(2p+3q)²=(4p-q+2p+3q)(4p-q-2p-3q)=(6p+2q)(2p-4q)=
=4(3p+q)(p-2q)
A²-B²=(A+B)(A-B)
A=4p-q, B=2p+3q
4 votes
Thanks 7
yulia08082007
у тебя не правильно
yulia08082007
извини я был не прав сорри
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Answers & Comments
=4(3p+q)(p-2q)
A²-B²=(A+B)(A-B)
A=4p-q, B=2p+3q