4.(решите срочно)...

July 2022 1 9 Report

Дана функция f:R->R, f(x)=x^2+(2m+1)x+m^2-3. Найдите действительные значения m , при которых минимум функции f равен -1/4.(решите срочно)

Answers & Comments

tamarabernukho $f(x)=x^2+(2m+1)x+m^2-3 \\ \\ f'(x)=2x+2m+1 \\ \\ f'(x)=0\\ \\ 2x=-(2m+1) \\ \\ x= -\frac{2m+1}{2} \\ \\ f( -\frac{2m+1}{2})=( -\frac{2m+1}{2})^2+(2m+1)* (-\frac{2m+1}{2})+m^2-3= \\ \\ \frac{4m^2-12-(4m^2+4m+1)}{4} = \frac{-4m-13}{4} =- \frac{1}{4} \\ \\ -4m=-1+13 \\ \\ 4m=-12 \\ \\ m=-3$

1 votes Thanks 3

Answers & Comments

petr nalil sok v stakan imeyushij formu pryamogo krugovogo cilindra s radiusom os

dlya chego lyudi izuchayut zemnuyu koru79f899dfc3f7fa55037da31f37872a0d 80787

reshite pozhalujsta budu ochen blagodarna tam nuzhno najti x i u

postroit pryamuyu prohodyashuyu cherez zadannuyu tochku i perpendikulyarnuyu k dannoj pr

raznost dvuh storon tupougolnyj ravnobedrennogo treugolnika ravna 8 sm a ego0ee7df8c78a94b5567648b6adf986062 56407

v treugolnike avs avvs tochki m i n serediny storon av i vs md i he perpendik

reshite pozhalujsta chast 2 nomer 2

est dva kanala peredachi dannyh esli vklyuchit pervyj na minutu a vtoroj na 30a946cadadfe399003acd82823c47127e 83933

po perimetru krugloj klumby nado vysadit 20 tyulpanov belyh i krasnyh krasny51c8f1466bb19ccf49cf95986232dd58 48696

dlya kakogo iz privedyonnyh znachenij chisla h istinno vyskazyvanie hgt2hlt

рекомендуемые вопросы

Helpful Links

Helpful Social