4sin^2(x)+2sinxcosx- cos^2 (x)=0. Created by dilya120878. geometriya-ru

4sin^2(x)+2sinxcosx- cos^2 (x)=0...

dilya120878 @dilya120878

August 2022 1 17 Report

4sin^2(x)+2sinxcosx- cos^2 (x)=0

Answers & Comments

danilka0511 Делим на cos^2(x)
4tg^2(x)+2*tg(x)-1=0
Пусть tg(x)= t
4t^2+2t-1=0
D=корень(5)
t1=(-2+корень(5))/4
t2=(-2-корень(5))/4
x1=arctg((-2+корень(5))/4)+ $\pi$ k
x2=arctg((-2-корень(5))/4)+ $\pi$ k

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