[tex]\displaystyle\bf\\\Bigg(\frac{5}{6}-\frac{1}{4} u^{8} \Bigg)^{2} =\Bigg(\frac{5}{6} \Bigg)^{2} -2\cdot \frac{5}{6}\cdot\frac{1}{4} u^{8} +\Bigg(\frac{1}{4} u^{8} \Bigg)^{2} =\frac{25}{36}-\frac{5}{12} u^{8} +\frac{1}{16} u^{16}[/tex]

Ответ:

(25/36)-(5/12)u⁸+(u¹⁶/16)

Объяснение:

(а-с)²=а²-2ас+с²

(5/6−1/4u⁸)²=(25/36)-2*(5/6)*(1/4)u⁸+(u¹⁶/16)=(25/36)-(5/12)u⁸+(u¹⁶/16)