Найти значения функции в указанных точках:
f(x)=-3+5x-3x^2 при x=-2; 0.3; 5;
g(x)=(5x/2x-1)-2 при x=-3.4; -1; 2целых1/4;
g(x)=1-(3x/4x-1) при x=-3.4; -1; 3.25;
f(x)=-3+5x-3x^2 при x=-2; 0.3; 5;
g(x)=(5x/2x-1)-2 при x=-3.4; -1; 2целых1/4;
g(x)=1-(3x/4x-1) при x=-3.4; -1; 3.25;
More Questions From This User See All
Answers & Comments
f(x)' =(4-3x)' (5x²+1)+(4-3x)(5x²+1)' =-3(5x²+1) +10x(4-3x)=-15x²-3+40x-30x²=
=-45x²+40x-3
3. f(x)= x⁵
x² -1
f(x)' = (x⁵)' (x²-1) - x⁵ (x² -1)' = 5x⁴ (x² -1) -2x*x⁵ = 5x⁶ - 5x⁴ -2x⁶ = 3x⁶ - 5x⁴
(x² -1)² (x² -1)² (x² -1)² (x² -1)²
4. f(x)=2√x + x⁻²
f(x)' = 2 * 1 - 2x⁻³ = 1 - 2
2√x √x x³