Найти корнень уравнения
1) log9(x+3)=log9(2x-16)
2) (1/4)^x-11=2
3)корень из( 2х+7)=5
log9(x+3)=log9(2x-16)
x+3=2x-16
(x+3)>0 x>-3
(2x-16)>0 x>8
x= 19
2) (1/4)^(x-11)=2
(2^-2)^(x-11)=2^1
-2(x-11)=1
x-11=-0,5
x=10,5
2х+7=25
2x=18
x=9
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log9(x+3)=log9(2x-16)
x+3=2x-16
(x+3)>0 x>-3
(2x-16)>0 x>8
x= 19
2) (1/4)^(x-11)=2
(2^-2)^(x-11)=2^1
-2(x-11)=1
x-11=-0,5
x=10,5
3)корень из( 2х+7)=5
2х+7=25
2x=18
x=9