4^x -18*2^x+32=02^(2x) - 18*2^x+32=0t=2^xt^2-18t+32=0t1+t2=18t1t2=32t=16;t=22^x=16; 2^x=2x=4; x=1Ответ: 4;1
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
4^x -18*2^x+32=0
2^(2x) - 18*2^x+32=0
t=2^x
t^2-18t+32=0
t1+t2=18
t1t2=32
t=16;t=2
2^x=16; 2^x=2
x=4; x=1
Ответ: 4;1