[tex]\displaystyle \left \{ {{4(x-2)-3(y+3)=1} \atop {3(x+2)-2(x-y)=5}} \right. \\\\(4x-3y)-4(x+2y)=18-4(-1)\\-11y=22\\y=-2\\4x-3(-2)=18\\x=3\\(x,y)=(3,-2)[/tex]