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Richi7322
@Richi7322
August 2022
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4^(x+2)-9*4^xбольше либо равно 28
там 4 в степени х+2
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irka1804
4^(x+2) = 4^x * 4^2 = 4^x * 16
4^(x+2) - 9 * 4^x >= 28
4^x * 16 - 9 * 4^x >= 28
4^x * (16 - 9) >= 28
4^x * 7 >= 28
4^x >= 4
x >= 1
1 votes
Thanks 1
shevtsovavalia
4ˣ⁺²-9*4ˣ≥28
4²*4ˣ-9*4ˣ≥28
4ˣ(16-9)≥28
4ˣ*7≥28
4ˣ≥4
x≥1
x∈[1;+∞)
2 votes
Thanks 1
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Answers & Comments
4^(x+2) - 9 * 4^x >= 28
4^x * 16 - 9 * 4^x >= 28
4^x * (16 - 9) >= 28
4^x * 7 >= 28
4^x >= 4
x >= 1
4²*4ˣ-9*4ˣ≥28
4ˣ(16-9)≥28
4ˣ*7≥28
4ˣ≥4
x≥1
x∈[1;+∞)