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sdgnfh
@sdgnfh
August 2022
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-4x^2+13x+12>=0
Срочно плиз
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DariosI
Verified answer
4x²-13x-12≤0
D=13²+4*4*12=169+192=361=19²
x₁=(13-19)/8=-6/8=-3/4=-0.75
x₂=(13+19)/8=4
4(x+0.75)(x-4)≤0
x∈[-0.75; 4]
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Verified answer
4x²-13x-12≤0D=13²+4*4*12=169+192=361=19²
x₁=(13-19)/8=-6/8=-3/4=-0.75
x₂=(13+19)/8=4
4(x+0.75)(x-4)≤0
x∈[-0.75; 4]