4X^2+6X-2=(X-1)^2
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4x^2+6x-2=(x-1)^2
(6x-2)-(x-1)^2+4x^2=0
(6x-2)+(4x^2-x^2+2x-1)=0
(6x-2)+(3x^2+2x-1)=0
2(3x-1)+(x+1)(3x-1)=0
(x+3)(3x-1)=0
1) x+3=0 => x=-3
2) 3x-1=0 => x=1/3
4X^2+6X-2=X^2-2x+1
3x2 + 8x - 3 = 0D = b2 - 4acD = 64 + 36 = 100 = 10^2
x1,2 = -b ± √D/2ax1 = -8 + 10/6 = 2/6 = 1/3x2 = -8 - 10/6 = - 18/6 = -3Ответ: x1 = 1/3 ; x2 = -3
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4x^2+6x-2=(x-1)^2
(6x-2)-(x-1)^2+4x^2=0
(6x-2)+(4x^2-x^2+2x-1)=0
(6x-2)+(3x^2+2x-1)=0
2(3x-1)+(x+1)(3x-1)=0
(x+3)(3x-1)=0
1) x+3=0 => x=-3
2) 3x-1=0 => x=1/3
4X^2+6X-2=(X-1)^2
4X^2+6X-2=X^2-2x+1
3x2 + 8x - 3 = 0
D = b2 - 4ac
D = 64 + 36 = 100 = 10^2
x1,2 = -b ± √D/2a
x1 = -8 + 10/6 = 2/6 = 1/3
x2 = -8 - 10/6 = - 18/6 = -3
Ответ: x1 = 1/3 ; x2 = -3