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miss1232
@miss1232
August 2022
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-4x^2+x+39≥(x+3)^2 решите неравенство
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nafanya2014
Verified answer
-4x²+x+39≥(x+3)²;
-4x²+x+39≥x²+6x+9;
5x²+5x-30≥0;
x²+x-6≥0
D=1-4*(-6)=1+24=25
x=(-1-5)/2=-3; x=(-1+5)/2=2
_+__ [-3] _-__ [2] _+__
О т в е т. х∈(-∞;-3]U[2;+∞)
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Answers & Comments
Verified answer
-4x²+x+39≥(x+3)²;-4x²+x+39≥x²+6x+9;
5x²+5x-30≥0;
x²+x-6≥0
D=1-4*(-6)=1+24=25
x=(-1-5)/2=-3; x=(-1+5)/2=2
_+__ [-3] _-__ [2] _+__
О т в е т. х∈(-∞;-3]U[2;+∞)