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azamat1594
@azamat1594
July 2022
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(4x+3)^2-(3x-1)^2=0
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Answers & Comments
1)![1 )(4x+3)^2-(3x-1)^2=0 \\\:16x^2+24x+9-9x^2+6x-1\\7x^2+30x+8=0x_{1,\:2}=\frac{-30\pm \sqrt{30^2-4\cdot \:7\cdot \:8}}{2\cdot \:7}x= -2/7 x=-4 1 )(4x+3)^2-(3x-1)^2=0 \\\:16x^2+24x+9-9x^2+6x-1\\7x^2+30x+8=0x_{1,\:2}=\frac{-30\pm \sqrt{30^2-4\cdot \:7\cdot \:8}}{2\cdot \:7}x= -2/7 x=-4](https://tex.z-dn.net/?f=1%20%29%284x%2B3%29%5E2-%283x-1%29%5E2%3D0%20%5C%5C%5C%3A16x%5E2%2B24x%2B9-9x%5E2%2B6x-1%5C%5C7x%5E2%2B30x%2B8%3D0x_%7B1%2C%5C%3A2%7D%3D%5Cfrac%7B-30%5Cpm%20%5Csqrt%7B30%5E2-4%5Ccdot%20%5C%3A7%5Ccdot%20%5C%3A8%7D%7D%7B2%5Ccdot%20%5C%3A7%7Dx%3D%20-2%2F7%20x%3D-4)