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LizaDesu
@LizaDesu
August 2022
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4^x+3*2^x=4
решите пожалуйста
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AzeezKh
(2^x)^2+3×2^x=4
2^x = t
t^2+3t-4=0
D=9+16=25
t1 = (-3+5)/2= 1
t2 = (-3-5)/2= -4
2^x = 1
2^x= 2^0
x1=0
2^x=-4
×2= не имеет решений.
Ответ: x=0
1 votes
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Answers & Comments
2^x = t
t^2+3t-4=0
D=9+16=25
t1 = (-3+5)/2= 1
t2 = (-3-5)/2= -4
2^x = 1
2^x= 2^0
x1=0
2^x=-4
×2= не имеет решений.
Ответ: x=0