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ANDKURSK
@ANDKURSK
August 2022
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2sin(pi/4+x)sin(pi/4+x)+sin^2x=0
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tatyanazubkova
Sin(π/2+2x)+sin^2x=0;
cos^2(2x)+sin^2x=0;
cos^2x-sin^2x+sin^2x=0;
cos^2x=0;
cosx=0;
x=π/2+πn,n∈Z
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Answers & Comments
cos^2(2x)+sin^2x=0;
cos^2x-sin^2x+sin^2x=0;
cos^2x=0;
cosx=0;
x=π/2+πn,n∈Z