Ответ:
4x³+x²-3x=0
Д=1^2 + 4*4*3=49=7
x1=(-1+7)/8=0,75
x2=(-1-7)/8=-1
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Ответ:
4x³+x²-3x=0
Д=1^2 + 4*4*3=49=7
x1=(-1+7)/8=0,75
x2=(-1-7)/8=-1