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Toplit
@Toplit
July 2022
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Система. найти x и y
1/3x +1/4y - 2=0
5x -y = 11
помогите решить пожалуйста, а то я чет туплю
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svetazuna
Verified answer
║
1/3x +1/4y - 2 = 0,
║
5x -y = 11,
из 2 ур-ия:
у = 5х - 11,
подставим во 2 ур-ие:
1/3х + 1/4*(5х-11) - 2 = 0,
1/3х + 5/4х - 11/4 - 2 = 0,
4/12х + 15/12х = 11/4 + 8/4
19/12х = 19/4,
х = 19/4 : 19/12,
х = 19/4 * 12/19,
х = 3,
у = 5*3 - 11 = 15 - 11 = 4,
ответ: (3; 4)
1 votes
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Answers & Comments
Verified answer
║1/3x +1/4y - 2 = 0,║5x -y = 11,
из 2 ур-ия:
у = 5х - 11,
подставим во 2 ур-ие:
1/3х + 1/4*(5х-11) - 2 = 0,
1/3х + 5/4х - 11/4 - 2 = 0,
4/12х + 15/12х = 11/4 + 8/4
19/12х = 19/4,
х = 19/4 : 19/12,
х = 19/4 * 12/19,
х = 3,
у = 5*3 - 11 = 15 - 11 = 4,
ответ: (3; 4)