(4+y)²-y(6+y)>0
16+y²+8y-6y-y²>0
2y>-16
y>-8
y∈(-8; +∞)
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(4+y)²-y(6+y)>0
16+y²+8y-6y-y²>0
2y>-16
y>-8
y∈(-8; +∞)