1) (x^2/4)+y^2=1
y^2=-(x^2/4)
y^2=-(x/2)^2
y=-x/2
2) x^2=8y
8y=x^2
y=x^2/8
y=1/8x^2
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Answers & Comments
1) (x^2/4)+y^2=1
y^2=-(x^2/4)
y^2=-(x/2)^2
y=-x/2
2) x^2=8y
8y=x^2
y=x^2/8
y=1/8x^2