4x² - ax - 5 = 0
По теореме Виета
х₁+х₂ = а/4
х₁·х₂ = - 5/4
х²₁ + х²₂ = (х₁ + х₂)² - 2х₁·х₂
(11/4) = (a/4)²-2·(-5/4)
1/4 = a^2/16
a = ±2
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Verified answer
4x² - ax - 5 = 0
По теореме Виета
х₁+х₂ = а/4
х₁·х₂ = - 5/4
х²₁ + х²₂ = (х₁ + х₂)² - 2х₁·х₂
(11/4) = (a/4)²-2·(-5/4)
1/4 = a^2/16
a = ±2