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ZloyShkolnick
@ZloyShkolnick
November 2021
2
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(5^-2 + 3^-3) * (1-(-3)^0)
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novokuz
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Решение во вложенном файле.
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vices
(5^-2 + 3^-3)*(1-1) (т.к. любое число в нулевой степени равно единице)
1-1=0
(5^-2 + 3^-3)*0=0
1 votes
Thanks 1
ZloyShkolnick
Хоть и сам понял,но все ровно спасмбо)
ZloyShkolnick
Спасибо*
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Verified answer
Решение во вложенном файле.1-1=0
(5^-2 + 3^-3)*0=0