m = 5кг
t₁ = -20℃
t₂ = 100℃
C = 4200 Дж/кг × ℃
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Q - ?
Q = m × c × △t
Q = 5 × 4200 × (100 -(-20)) = 21000 × 120 = 2520000 Дж = 2520 кДж
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Answers & Comments
Дано:
m = 5кг
t₁ = -20℃
t₂ = 100℃
C = 4200 Дж/кг × ℃
----------------------------------
Q - ?
Розв'язок:
Q = m × c × △t
Q = 5 × 4200 × (100 -(-20)) = 21000 × 120 = 2520000 Дж = 2520 кДж