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lizaku1998
@lizaku1998
August 2022
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решите уравнение log(х^2+3x-3) по основанию 1/5=-2
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sangers1959
Verified answer
Log₁/₅(x²+3x-3)=-2
ОДЗ: x²+3x-3>0 D=21 x≈-3,8 x≈0,8 x∈(-∞-3,8)U(0,8;+∞)
x²+3x-3=(1/5)⁻²
x²+3x-3=5²
x²+3x-3-25=0
x²+3x-28=0 D=121
x₁=-7 x₂=4
Ответ: х₁=-7 х₂=4.
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Answers & Comments
Verified answer
Log₁/₅(x²+3x-3)=-2ОДЗ: x²+3x-3>0 D=21 x≈-3,8 x≈0,8 x∈(-∞-3,8)U(0,8;+∞)
x²+3x-3=(1/5)⁻²
x²+3x-3=5²
x²+3x-3-25=0
x²+3x-28=0 D=121
x₁=-7 x₂=4
Ответ: х₁=-7 х₂=4.