Verified answer

Ответ:

5 √3 - √27 - √6 (√2 +1)

[tex] = 5 \sqrt{3} - 3 \sqrt{3} - \sqrt{12} - \sqrt{6} = 5 \sqrt{3} - 3 \sqrt{3} - 2 \sqrt{3} - \sqrt{6} = 0 - \sqrt{6} = - \sqrt{6} [/tex]