[tex]\displaystyle -\frac{3}{5}(2x-\frac{2}{3})=-\frac{1}{5}x-\frac{3}{5}\\ \\-\frac{6}{5}x+\frac{2}{5}=-\frac{1}{5}x-\frac{3}{5}\\ \\-6x+2=-x-3\\ -6x+x=-3-2\\ -5x=-5\\ x=1[/tex]
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[tex]\displaystyle -\frac{3}{5}(2x-\frac{2}{3})=-\frac{1}{5}x-\frac{3}{5}\\ \\-\frac{6}{5}x+\frac{2}{5}=-\frac{1}{5}x-\frac{3}{5}\\ \\-6x+2=-x-3\\ -6x+x=-3-2\\ -5x=-5\\ x=1[/tex]