[tex] \frac{4}{5} x + 1 \frac{1}{3} = 1 \frac{2}{5} \\ \frac{4}{5} x = 1 \frac{2}{5} - 1 \frac{1}{3} \\ \frac{4}{5} x = 1 \frac{6}{15} - 1 \frac{5}{15} \\ \frac{4}{5} x = \frac{1}{15} \\ x = \frac{1}{15} \div \frac{4}{5} \\ x = \frac{5}{15 \times 4} \\ x = \frac{1}{12} [/tex]
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[tex] \frac{4}{5} x + 1 \frac{1}{3} = 1 \frac{2}{5} \\ \frac{4}{5} x = 1 \frac{2}{5} - 1 \frac{1}{3} \\ \frac{4}{5} x = 1 \frac{6}{15} - 1 \frac{5}{15} \\ \frac{4}{5} x = \frac{1}{15} \\ x = \frac{1}{15} \div \frac{4}{5} \\ x = \frac{5}{15 \times 4} \\ x = \frac{1}{12} [/tex]