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DmaExectionSDK
@DmaExectionSDK
July 2022
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Найдите Sin a если cosa=(2√6)/5 a∈(0:пи деленое на 2)
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belcatya
Sin²α+cos²α=1, отсюда sin²α=1-cos²α
sinα=√1-cos²α=√1-
((2√6)/5)
²=√1-4*6/25=√1-24/25=√1/25=1/5
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Answers & Comments
sinα=√1-cos²α=√1-((2√6)/5)²=√1-4*6/25=√1-24/25=√1/25=1/5