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Pandorka
@Pandorka
June 2021
1
22
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Вычислите ctg(arccos(-4/5)+ arcctg(-1))
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komradivaniva
X=arccos(-4?5)<=>cos x=-4/5 π/2≤x≤
π=> ctg=-4/3.
y=arcctg(-1)<=>ctg y--1 & 0<y<
π
ctg(x+y)=(ctg x-1)/(ctg x+ ctg y)=
{(-4/3)(-1)-1
}/(-4/3-1)=(1/3)/(-7/3)=-1/7
0 votes
Thanks 1
Pandorka
а откуда там -4/3,
Pandorka
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Answers & Comments
y=arcctg(-1)<=>ctg y--1 & 0<y< π
ctg(x+y)=(ctg x-1)/(ctg x+ ctg y)={(-4/3)(-1)-1}/(-4/3-1)=(1/3)/(-7/3)=-1/7