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asel99
@asel99
July 2022
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1. 2sin2x-1=
2. (sinx+tgx*ctgx)=
3. ( tg x/5*ctg x/5-cosx) =
4. 1-2cos^2x=
помогите Пожалуйста
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фиксик777
2sin2x=-1 sin2x=-1/2 2х=arcsin(-1/2) 2x=-pi/6 x=-pi/12 Ответ: x=-pi/12+n*pi
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