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555559955
@555559955
August 2022
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Помогите пож.решить:
(6-1,2х)(-х-4х+10х-15)=0; -2х+1/4=-2-3х/5; х в 3 степени-х=0;
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ndusha
Verified answer
(6-1,2х)(-х-4х+10х-15)=0
(6-1,2х)(5х-15)=0
1,2(5-х)*5(х-3)=0
5-х=0 х-3=0
х₁=5 х₂=3
-2х+1/4=-2-3х/5
-2х+3х/5=-2-1/4
-2х+0,6х=-2-0,25
-1,4х=-2,25
х=2,25/1,4=225/140=45/28=1 17/28
2).х³-х=0
х(х²-1)=0
х(х-1)(х+1)=0
х=0 х-1=0 х+1=0
х₁=0 х₂=1 х₃=-1
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Answers & Comments
Verified answer
(6-1,2х)(-х-4х+10х-15)=0(6-1,2х)(5х-15)=0
1,2(5-х)*5(х-3)=0
5-х=0 х-3=0
х₁=5 х₂=3
-2х+1/4=-2-3х/5
-2х+3х/5=-2-1/4
-2х+0,6х=-2-0,25
-1,4х=-2,25
х=2,25/1,4=225/140=45/28=1 17/28
2).х³-х=0
х(х²-1)=0
х(х-1)(х+1)=0
х=0 х-1=0 х+1=0
х₁=0 х₂=1 х₃=-1