В треугольнике АВС АС=ВС, АВ=72, косинус А=4/5. Найдите высоту СН.
AH=AB/2
AH=72/2=36
cosA=4/5
cosA=AH/AC
4/5=36/AC
AC=45
CH^2=AC^2-AH^2
CH^2=2025-1296
CH=27
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AH=AB/2
AH=72/2=36
cosA=4/5
cosA=AH/AC
4/5=36/AC
AC=45
CH^2=AC^2-AH^2
CH^2=2025-1296
CH=27