найдите cos(t+4пи),если cos(2пи-t)=-3/5
помогите,пожалуйста,решить:)))
| sin(a) | = √(1 - cos²(a) = 4/5Поскольку п<a<3/2п , то sin(a) = - 4/5tg(a) = sin(a)/cos(a) = (- 4/5 ) / (-3/5) = 4/3
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| sin(a) | = √(1 - cos²(a) = 4/5
Поскольку п<a<3/2п , то sin(a) = - 4/5
tg(a) = sin(a)/cos(a) = (- 4/5 ) / (-3/5) = 4/3