Ответ:
6,24
Объяснение:
b₂=1/5; q=5
Формула n-го члена bₙ=b₁qⁿ⁻¹
b₂=b₁q
1/5=b₁·5
b₁=1/5 ÷5
b₁=1/5 ·1/5
b₁=1/25
Сумма n первых членов Sₙ=(b₁(qⁿ-1))/(q-1)
S₄=(b₁(q⁴-1))/(q-1)=(1/25 ·(5⁴-1))/(5-1)=(625-1)/(25·4)=624/100=6,24
Sn =b₁(qⁿ -1) / (q-1) ; bn =b₁qⁿ⁻¹ || b₂ =b₁*q ||
S₄ =b₁(q⁴ -1) / (q-1) = (b₂/q)(q⁴ -1) / (q-1) =b₂(q⁴ -1) / q(q-1)
S₄ =(1/5)*(5⁴ -1) /5(5-1)= (5⁴ -1)/5²(5-1) = (625-1) /25*4 =624/100 =6,24.
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Answers & Comments
Ответ:
6,24
Объяснение:
b₂=1/5; q=5
Формула n-го члена bₙ=b₁qⁿ⁻¹
b₂=b₁q
1/5=b₁·5
b₁=1/5 ÷5
b₁=1/5 ·1/5
b₁=1/25
Сумма n первых членов Sₙ=(b₁(qⁿ-1))/(q-1)
S₄=(b₁(q⁴-1))/(q-1)=(1/25 ·(5⁴-1))/(5-1)=(625-1)/(25·4)=624/100=6,24
Verified answer
Ответ:
6,24
Объяснение:
Sn =b₁(qⁿ -1) / (q-1) ; bn =b₁qⁿ⁻¹ || b₂ =b₁*q ||
S₄ =b₁(q⁴ -1) / (q-1) = (b₂/q)(q⁴ -1) / (q-1) =b₂(q⁴ -1) / q(q-1)
S₄ =(1/5)*(5⁴ -1) /5(5-1)= (5⁴ -1)/5²(5-1) = (625-1) /25*4 =624/100 =6,24.