#5 С помощью формулы куба суммы преобразуйте в многочлен:
а) (n + 1)³
б) (4b + 5)³
в) (2 +6x)³
г) (g + 4)³
а) (n + 1)³
б) (4b + 5)³
в) (2 +6x)³
г) (g + 4)³
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Verified answer
(n+1)^3 = n^3 + 3n^2 + 3n + 1(4b+5)^3 = (4b)^3 + 3(4b)^2*5 + 3(4b)*5^2 + 5^3 =
= 64b^3 + 240b^2 + 300b + 125
(6x+2)^3 = (6x)^3 + 3(6x)^2*2 + 3(6x)*2^2 + 2^3 =
= 216x^3 + 216x^2 + 72x + 8
(g+4)^3 = g^3 + 3g^2*4 + 3g*4^2 + 4^3 = g^3 + 12g^2 + 48g + 64