Ответ:
(315+8√21)/50
Объяснение:
sinx=−2/5, π<x<3π/2⇒sin2x+6,3=?
cos²x=1-sin²x=1-(-2/5)²=1-4/25=21/25
π<x<3π/2⇒cosx<0⇒cosx=-√(21/25)=-√21/5
sin2x=2sinx•cosx=2•(−2/5)•(-√21/5)=4√21/25
sin2x+6,3=4√21/25+6,3=(315+8√21)/50
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Ответ:
(315+8√21)/50
Объяснение:
sinx=−2/5, π<x<3π/2⇒sin2x+6,3=?
cos²x=1-sin²x=1-(-2/5)²=1-4/25=21/25
π<x<3π/2⇒cosx<0⇒cosx=-√(21/25)=-√21/5
sin2x=2sinx•cosx=2•(−2/5)•(-√21/5)=4√21/25
sin2x+6,3=4√21/25+6,3=(315+8√21)/50