1.
Решим дискриминант:
x²-10x+25=0
a=1 b=-10 c=25
D=b²-4ac=> (-10)²-4*1*25 = 100-100 = 0=0, 1 корень.
x =
x₁ =
Получается:
2. =
Тут тот же дискриминант, значит:
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
1.
Решим дискриминант:
x²-10x+25=0
a=1 b=-10 c=25
D=b²-4ac=> (-10)²-4*1*25 = 100-100 = 0=0, 1 корень.
x =
x₁ =
Получается:
2.
= 
Тут тот же дискриминант, значит: